August Library (8/24/09)
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Probes, Samples, and Calculations
Probes:
Jan09-1: 12.4 ng/ul, 46417 probes; 376 nM Jan09-2: 16.3 ng/ul, 53493 probes; 494 nM Jan09-3: 7.8 ng/ul, 53828 probes; 236 nM
Samples:
Sample # Sample name Amount Concentration 1 MH001 1+2 xHeaIII 10 ul 102.7 ng/ul 2 MH010B xMboI 6 ul 183.4 ng/ul 3 MH010B xDpnI 10 ul 100 ng/ul 4 TCF #3 6 ul 200 ng/ul 5 DK4 #2 17 ul 58.9 ng/ul 6 TK4 #2 18 ul 55.9 ng/ul 7 TK9 12 ul 89.4 ng/ul 8 Pol II 10 ul 99.7 ng/ul
Calculations
Probe: Target ratio is 100:1 The mass of one genome is 3pg: 200ng of DNA is equal to 200ng/3pg. The amount of probe needed is 200ng/3pg * 250 for each target, and the total amount of probe is (200ng/3pg * 100 * 46417)/(6.0 * 10^23) Example Assume the concentration of probe Jan09-1 to be 10ng/ul. Knowing the length of the probe is ~100 bases and 1 base = 330 Daltons (1bp = 2 bases = 660 Da). Solve: Concentration of Jan09-1 probe: 10ng/ul / 33000 = 303 nM Volume of probe needed= (200ng/3pg * 100 * 46417)/(6.0 * 10^23 * 303 nM) = 1.73ul